today i am going to tell u about factorial notation....
The symbon n! means to multiply all the positive integers from n consecutively down to 1
n!=n(n-1)(n-2).........(3) (2) (1), where n is an that element which positive integers.
exp. 1=
0!=1 it is always defined as 1
exp.2=
5!=5 (5-1)(5-2)(5-3)(5-4)(5-5)
5*4*3*2*1=120
exp.3
11!= 11*10*9*8*7*6!= 279n17600
exp.4=
n(n-5)!=24(n-6)!
n(n-5) ( n-6)!=24 (n-6)!
cancel (n-6)!
n(n-5)=24
n*n-5n-24=0
n*n-8n+3n-24=0
n(n-8)+3(n-8)=0
(n-8) (n+3)=0
n-8=0 or n+3=0
n=8 or n= (-3)
n=-3 reject it bcz n is an elemnt of negative integer....
check ans... put the value of n=8 in eq.
8(8-5)!=24(8-6)!
8(3)!=24 (2)!
8*3*2*1=24*2*1
48=48
L.H.S=R.H.S
so its the easiest way to solve.........the factorial notation
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